Integrand size = 12, antiderivative size = 137 \[ \int (a+b \sin (e+f x))^4 \, dx=\frac {1}{8} \left (8 a^4+24 a^2 b^2+3 b^4\right ) x-\frac {a b \left (19 a^2+16 b^2\right ) \cos (e+f x)}{6 f}-\frac {b^2 \left (26 a^2+9 b^2\right ) \cos (e+f x) \sin (e+f x)}{24 f}-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f} \]
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Time = 0.11 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2735, 2832, 2813} \[ \int (a+b \sin (e+f x))^4 \, dx=-\frac {a b \left (19 a^2+16 b^2\right ) \cos (e+f x)}{6 f}-\frac {b^2 \left (26 a^2+9 b^2\right ) \sin (e+f x) \cos (e+f x)}{24 f}+\frac {1}{8} x \left (8 a^4+24 a^2 b^2+3 b^4\right )-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f} \]
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Rule 2735
Rule 2813
Rule 2832
Rubi steps \begin{align*} \text {integral}& = -\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac {1}{4} \int (a+b \sin (e+f x))^2 \left (4 a^2+3 b^2+7 a b \sin (e+f x)\right ) \, dx \\ & = -\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac {1}{12} \int (a+b \sin (e+f x)) \left (a \left (12 a^2+23 b^2\right )+b \left (26 a^2+9 b^2\right ) \sin (e+f x)\right ) \, dx \\ & = \frac {1}{8} \left (8 a^4+24 a^2 b^2+3 b^4\right ) x-\frac {a b \left (19 a^2+16 b^2\right ) \cos (e+f x)}{6 f}-\frac {b^2 \left (26 a^2+9 b^2\right ) \cos (e+f x) \sin (e+f x)}{24 f}-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f} \\ \end{align*}
Time = 0.49 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.77 \[ \int (a+b \sin (e+f x))^4 \, dx=\frac {-96 a b \left (4 a^2+3 b^2\right ) \cos (e+f x)+32 a b^3 \cos (3 (e+f x))+3 \left (4 \left (8 a^4+24 a^2 b^2+3 b^4\right ) (e+f x)-8 \left (6 a^2 b^2+b^4\right ) \sin (2 (e+f x))+b^4 \sin (4 (e+f x))\right )}{96 f} \]
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Time = 1.60 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.85
method | result | size |
derivativedivides | \(\frac {b^{4} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {4 a \,b^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+6 a^{2} b^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-4 a^{3} b \cos \left (f x +e \right )+a^{4} \left (f x +e \right )}{f}\) | \(116\) |
default | \(\frac {b^{4} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {4 a \,b^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+6 a^{2} b^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-4 a^{3} b \cos \left (f x +e \right )+a^{4} \left (f x +e \right )}{f}\) | \(116\) |
parts | \(a^{4} x +\frac {b^{4} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )}{f}-\frac {4 a^{3} b \cos \left (f x +e \right )}{f}+\frac {6 a^{2} b^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )}{f}-\frac {4 a \,b^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3 f}\) | \(120\) |
risch | \(a^{4} x +3 x \,a^{2} b^{2}+\frac {3 x \,b^{4}}{8}-\frac {4 a^{3} b \cos \left (f x +e \right )}{f}-\frac {3 a \,b^{3} \cos \left (f x +e \right )}{f}+\frac {b^{4} \sin \left (4 f x +4 e \right )}{32 f}+\frac {a \,b^{3} \cos \left (3 f x +3 e \right )}{3 f}-\frac {3 \sin \left (2 f x +2 e \right ) a^{2} b^{2}}{2 f}-\frac {\sin \left (2 f x +2 e \right ) b^{4}}{4 f}\) | \(124\) |
parallelrisch | \(\frac {96 a^{4} f x +288 a^{2} b^{2} f x +36 b^{4} f x +3 b^{4} \sin \left (4 f x +4 e \right )+32 a \,b^{3} \cos \left (3 f x +3 e \right )-144 \sin \left (2 f x +2 e \right ) a^{2} b^{2}-24 \sin \left (2 f x +2 e \right ) b^{4}-384 a^{3} b \cos \left (f x +e \right )-288 \cos \left (f x +e \right ) a \,b^{3}-384 a^{3} b -256 a \,b^{3}}{96 f}\) | \(127\) |
norman | \(\frac {\left (a^{4}+3 a^{2} b^{2}+\frac {3}{8} b^{4}\right ) x +\left (a^{4}+3 a^{2} b^{2}+\frac {3}{8} b^{4}\right ) x \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (4 a^{4}+12 a^{2} b^{2}+\frac {3}{2} b^{4}\right ) x \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (4 a^{4}+12 a^{2} b^{2}+\frac {3}{2} b^{4}\right ) x \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (6 a^{4}+18 a^{2} b^{2}+\frac {9}{4} b^{4}\right ) x \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )-\frac {24 a^{3} b +16 a \,b^{3}}{3 f}-\frac {8 a^{3} b \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}-\frac {2 \left (12 a^{3} b +8 a \,b^{3}\right ) \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}-\frac {4 \left (18 a^{3} b +16 a \,b^{3}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{3 f}-\frac {3 b^{2} \left (8 a^{2}+b^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{4 f}+\frac {3 b^{2} \left (8 a^{2}+b^{2}\right ) \left (\tan ^{7}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}-\frac {b^{2} \left (24 a^{2}+11 b^{2}\right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}+\frac {b^{2} \left (24 a^{2}+11 b^{2}\right ) \left (\tan ^{5}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{4}}\) | \(373\) |
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Time = 0.30 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.77 \[ \int (a+b \sin (e+f x))^4 \, dx=\frac {32 \, a b^{3} \cos \left (f x + e\right )^{3} + 3 \, {\left (8 \, a^{4} + 24 \, a^{2} b^{2} + 3 \, b^{4}\right )} f x - 96 \, {\left (a^{3} b + a b^{3}\right )} \cos \left (f x + e\right ) + 3 \, {\left (2 \, b^{4} \cos \left (f x + e\right )^{3} - {\left (24 \, a^{2} b^{2} + 5 \, b^{4}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{24 \, f} \]
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Time = 0.20 (sec) , antiderivative size = 240, normalized size of antiderivative = 1.75 \[ \int (a+b \sin (e+f x))^4 \, dx=\begin {cases} a^{4} x - \frac {4 a^{3} b \cos {\left (e + f x \right )}}{f} + 3 a^{2} b^{2} x \sin ^{2}{\left (e + f x \right )} + 3 a^{2} b^{2} x \cos ^{2}{\left (e + f x \right )} - \frac {3 a^{2} b^{2} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {4 a b^{3} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {8 a b^{3} \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac {3 b^{4} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac {3 b^{4} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac {3 b^{4} x \cos ^{4}{\left (e + f x \right )}}{8} - \frac {5 b^{4} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} - \frac {3 b^{4} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} & \text {for}\: f \neq 0 \\x \left (a + b \sin {\left (e \right )}\right )^{4} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.82 \[ \int (a+b \sin (e+f x))^4 \, dx=a^{4} x + \frac {3 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} b^{2}}{2 \, f} + \frac {4 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a b^{3}}{3 \, f} + \frac {{\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} b^{4}}{32 \, f} - \frac {4 \, a^{3} b \cos \left (f x + e\right )}{f} \]
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Time = 0.28 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.79 \[ \int (a+b \sin (e+f x))^4 \, dx=\frac {a b^{3} \cos \left (3 \, f x + 3 \, e\right )}{3 \, f} + \frac {b^{4} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} + \frac {1}{8} \, {\left (8 \, a^{4} + 24 \, a^{2} b^{2} + 3 \, b^{4}\right )} x - \frac {{\left (4 \, a^{3} b + 3 \, a b^{3}\right )} \cos \left (f x + e\right )}{f} - \frac {{\left (6 \, a^{2} b^{2} + b^{4}\right )} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \]
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Time = 6.63 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.83 \[ \int (a+b \sin (e+f x))^4 \, dx=\frac {\frac {3\,b^4\,\sin \left (4\,e+4\,f\,x\right )}{4}-6\,b^4\,\sin \left (2\,e+2\,f\,x\right )+8\,a\,b^3\,\cos \left (3\,e+3\,f\,x\right )-36\,a^2\,b^2\,\sin \left (2\,e+2\,f\,x\right )-72\,a\,b^3\,\cos \left (e+f\,x\right )-96\,a^3\,b\,\cos \left (e+f\,x\right )+24\,a^4\,f\,x+9\,b^4\,f\,x+72\,a^2\,b^2\,f\,x}{24\,f} \]
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